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Correct exception catching

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asyncio.Task.result() is simply going to throw the exception in
asyncio.Task.exception(), there is no need to manually throw it.
This commit is contained in:
atse 2024-07-09 12:27:35 +08:00
parent 6388aac023
commit 759b9e57a1
1 changed files with 11 additions and 13 deletions
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24
pytec/pytec/gui/model/thermostat.py
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@ -40,19 +40,17 @@ class Thermostat(QObject, metaclass=PropertyMeta):
self.task = asyncio.create_task(self.update_params())
while True:
if self.task.done():
if self.task.exception() is not None:
try:
raise self.task.exception()
except (
Exception,
TimeoutError,
asyncio.exceptions.TimeoutError,
):
logging.error(
"Encountered an error while updating parameter tree.",
exc_info=True,
)
_ = self.task.result()
try:
_ = self.task.result()
except (
Exception,
TimeoutError,
asyncio.exceptions.TimeoutError,
):
logging.error(
"Encountered an error while updating parameter tree.",
exc_info=True,
)
self.task = asyncio.create_task(self.update_params())
await asyncio.sleep(self._update_s)