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type of second operand of bitshifts #336

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opened 2023-10-06 12:54:56 +08:00 by sb10q · 0 comments
sb10q commented 2023-10-06 12:54:56 +08:00
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Currently A << B and A >> B need A and B to be of the same type.

For int64 this means we need a 64-bit B. Does this make sense? Shouldn't it always be int32?

Currently ``A << B`` and ``A >> B`` need ``A`` and ``B`` to be of the same type. For ``int64`` this means we need a 64-bit ``B``. Does this make sense? Shouldn't it always be ``int32``?
sb10q closed this issue 2023-11-09 12:16:21 +08:00
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Reference: M-Labs/nac3#336
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